将原本10进制的数位,改成2进制的数位转移就好了
#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
typedef long long ll;
ll dp[35][35][35];
int bit[12];
ll dfs(int pos,int cn0,int cn1,int lim,int z)
{
if(pos==-1)
{
if(z==1) return 0;
if(cn0>=cn1) return 1;
return 0;
}
if(!lim&&dp[pos][cn0][cn1]!=-1) return dp[pos][cn0][cn1];
ll ans=0;
int en=lim?bit[pos]:1;
for(int i=0;i<=en;i++)
{
if(z&&i==0) ans+=dfs(pos-1,0,0,0,1);
else
{
if(i==0) ans+=dfs(pos-1,cn0+1,cn1,lim&&i==en,0);
if(i==1) ans+=dfs(pos-1,cn0,cn1+1,lim&&i==en,0);
}
}
if(!lim&&dp[pos][cn0][cn1]==-1) dp[pos][cn0][cn1]=ans;
return ans;
}
ll solve(ll x)
{
int len=0;
while(x)
{
bit[len++]=x%2;
x/=2;
}
return dfs(len-1,0,0,1,1);
}
int main()
{
memset(dp,-1,sizeof(dp));
ll st,en;
while(~scanf("%lld%lld",&st,&en))
printf("%lld\n",solve(en)-solve(st-1));
}