poj 3650 The Seven Percent Solution

最新推荐文章于 2020-01-15 16:51:58 发布

原创最新推荐文章于 2020-01-15 16:51:58 发布 · 284 阅读

0 ·

CC 4.0 BY-SA版权

模拟专栏收录该内容

41 篇文章

订阅专栏

本文介绍了一种URI百分比编码的方法，针对特定字符进行转换，确保在网络传输中正确无误。文章通过示例展示了如何将保留字符转换为对应的百分比编码形式。

The Seven Percent Solution

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 7908		Accepted: 5323

Description

Uniform Resource Identifiers (or URIs) are strings like http://icpc.baylor.edu/icpc/, mailto:foo@bar.org, ftp://127.0.0.1/pub/linux, or even just readme.txt that are used to identify a resource, usually on the Internet or a local computer. Certain characters are reserved within URIs, and if a reserved character is part of an identifier then it must be percent-encoded by replacing it with a percent sign followed by two hexadecimal digits representing the ASCII code of the character. A table of seven reserved characters and their encodings is shown below. Your job is to write a program that can percent-encode a string of characters.

Character	Encoding
" " (space)	%20
"`!`" (exclamation point)	%21
"`$`" (dollar sign)	%24
"`%`" (percent sign)	%25
"`(`" (left parenthesis)	%28
"`)`" (right parenthesis)	%29
"`*`" (asterisk)	%2a

Input

The input consists of one or more strings, each 1–79 characters long and on a line by itself, followed by a line containing only "#" that signals the end of the input. The character "#" is used only as an end-of-input marker and will not appear anywhere else in the input. A string may contain spaces, but not at the beginning or end of the string, and there will never be two or more consecutive spaces.

Output

For each input string, replace every occurrence of a reserved character in the table above by its percent-encoding, exactly as shown, and output the resulting string on a line by itself. Note that the percent-encoding for an asterisk is %2a (with a lowercase "a") rather than %2A (with an uppercase "A").

Sample Input

Happy Joy Joy!
http://icpc.baylor.edu/icpc/
plain_vanilla
(**)
?
the 7% solution
#

Sample Output

Happy%20Joy%20Joy%21
http://icpc.baylor.edu/icpc/
plain_vanilla
%28%2a%2a%29
?
the%207%25%20solution

Source

Mid-Central USA 2007

先把输进来的字符串存起来，再根据题意一个一个的遍历输出就可以了。

#include<iostream>
#include<cstring>
#include<string>
#include<cstdio>
using namespace std;
int n;
int main(){
	char a[1111];
	while(gets(a))
	{
		int len=strlen(a);
		if(a[0]=='#'&&len==1)
		break;
		for(int i=0;i<len;i++)
		{
			if(a[i]==' ')cout<<"%20";
			else if(a[i]=='!')cout<<"%21";
			else if(a[i]=='$')cout<<"%24";
			else if(a[i]=='%')cout<<"%25";
			else if(a[i]=='(')cout<<"%28";
			else if(a[i]==')')cout<<"%29";
			else if(a[i]=='*')cout<<"%2a";
			else cout<<a[i];
		}
		cout<<endl;
	}
	return 0;
}