292. Nim Game

本文介绍了一种数学方法来判断Nim游戏的胜负。当玩家面对堆中石头数量为4的倍数时将输掉游戏。文章提供了一个简洁的Python实现,通过取模运算快速判断玩家是否能赢得游戏。

292. Nim Game

Leetcode link for this question

Discription:

You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

Analyze:

It is a math problem. When the person facing 4 stones in the heap(more generally, the number of stones is multiple of 4), he will lose the game.

Code 1:

class Solution(object):
    def canWinNim(self, n):
        """
        :type n: int
        :rtype: bool
        """
        return bool(n%4)

Submission Result:

Status: Accepted
Runtime: 68 ms
Ranking: beats 67.24%

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值