67. Add Binary
Leetcode link for this question
Discription:
Given two binary strings, return their sum (also a binary string).
For example,
a = “11”
b = “1”
Return “100”.
Code 1:
class Solution(object):
def addBinary(self, a, b):
"""
:type a: str
:type b: str
:rtype: str
"""
la =len(a)
lb=len(b)
if la<lb:
return self.addBinary(b,a)
b='0'*(la-lb)+b
carry=0
a=list(a)
for i in range(la-1,-1,-1):
sum=int(a[i])+int(b[i])+carry
if sum==1 or sum==0:
a[i]=str(sum)
carry=0
else:
a[i]=str(sum-2)
carry=1
if carry==1:
return '1'+''.join(a)
return ''.join(a)
Submission Result:
Status: Accepted
Runtime: 80 ms
Ranking: beats 22.46%
Code 2(recursive function):
class Solution(object):
def addBinary(self, a, b):
"""
:type a: str
:type b: str
:rtype: str
"""
if len(a)==0: return b
if len(b)==0: return a
if a[-1] == '1' and b[-1] == '1':
return self.addBinary(self.addBinary(a[0:-1], b[0:-1]), '1') + '0'
else:
return self.addBinary(a[0:-1], b[0:-1]) + str(int(a[-1]) + int(b[-1]))
Submission Result:
Status: Accepted
Runtime: 72 ms
Ranking: beats 44.74%
二进制字符串相加
本文介绍了如何实现两个二进制字符串的相加操作,并提供了两种不同的Python实现方法:一种是迭代方法,通过逐位相加并处理进位;另一种是递归方法,通过不断去除最后一位并递归调用直至字符串为空。
714

被折叠的 条评论
为什么被折叠?



