A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?
Above is a 3 x 7 grid. How many possible unique paths are there?
Note: m and n will be at most 100.
题意:有一个m * n的二维数组,求出从(0,0)到(m-1,n-1)有多少条路,每次移动只能向下或向右
思路:
dp算法。
dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
代码:
public static int uniquePaths(int m, int n)
{
int[][] dp = new int[m][n];
for(int i = 0; i < m; i++)
dp[i][0] = 1;
for(int j = 0; j < n; j++)
dp[0][j] = 1;
for(int i = 1; i < m; i++)
for(int j = 1; j < n; j++)
dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
return dp[m - 1][n - 1];
}