目录
1. Move block of memory
#include <string.h>
void * memmove ( void * destination, const void * source, size_t num );
Copies the values of num bytes from the location pointed by source to the memory block pointed by destination. Copying takes place as if an intermediate buffer were used, allowing the destination and source to overlap.
The underlying type of the objects pointed by both the source and destination pointers are irrelevant for this function; The result is a binary copy of the data.
The function does not check for any terminating null character in source - it always copies exactly num bytes.
To avoid overflows, the size of the arrays pointed by both the destination and source parameters, shall be at least num bytes.
上述内容是 cplusplus 对 memmove 函数的介绍,
可以看出 memmove 函数从源 src 所指的内存地址的起始位置开始复制 count 个字节到目标 dest 所指的内存地址的起始位置中,允许目标字符串与源字符串重叠。
2. 源代码
#include <stdio.h>
#include <assert.h>
#define MAX_ARR 6
void *Memmove(void *dest, const void *src, size_t count) {
assert((NULL != src) && (NULL != dest));
void *ret = dest;
if (dest < src) {
while (count--)
#if 0
// left -> right
*(char *)ret = *(char *)src;
ret = (char *)ret + 1;
src = (const char *)src + 1;
#endif
*(char *)ret++ = *(char *)src++;
} else {
while (count--)
// right -> left
*((char *)ret + count) = *((char *)src + count);
}
return dest;
}
void print_int_arr(int arr[], int len) {
int i = 0;
for (; i < len; ++i)
printf("%-4d", arr[i]);
putchar('\n');
}
void test_int_arr() {
int i = 0;
int a[MAX_ARR] = {0};
for (i = 0; i < MAX_ARR; ++i)
a[i] = i + 1;
puts("call Memmove a array before:");
print_int_arr(a, MAX_ARR);
puts("call Memmove a array after:");
Memmove(a + 2, a, sizeof(int) * 2);
print_int_arr(a, MAX_ARR);
}
int main(void) {
test_int_arr();
return 0;
}
3. 输出结果
call Memmove a array before:
1 2 3 4 5 6
call Memmove a array after:
1 2 1 2 5 6