Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array [2,3,1,2,4,3] and s
= 7,
the subarray [4,3] has the minimal length under the problem constraint.
class Solution {
public:
int minSubArrayLen(int s, vector<int>& nums) {
int minlen = numeric_limits<int>::max();
int start = -1;
int sum = 0;
for (int i = 0; i < nums.size(); ++i) {
sum += nums[i];
while (sum >= s) {
minlen = min(minlen, i - start);
sum -= nums[++start];
}
}
if (minlen == INT_MAX)
return 0;
return minlen;
}
};
本文介绍了一种寻找具有最小长度且元素之和大于等于给定值s的子数组的方法。通过一个具体的例子进行说明,即在数组[2,3,1,2,4,3]中找到满足条件s=7的最小子数组。
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