struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
public:
TreeNode* Convert2BST(vector<int>& num, int start, int end)
{
if(start > end)
return NULL;
int mid = (start+end)/2;
TreeNode* pNode = new TreeNode(num[mid]);
pNode->left = Convert2BST(num, start, mid-1);
pNode->right = Convert2BST(num, mid+1, end);
return pNode;
}
TreeNode *sortedArrayToBST(vector<int> &num) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
return Convert2BST(num, 0, num.size()-1);
}
};
second time
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBSTUtil(vector<int>& num, int start, int end)
{
if(start > end) return NULL;
int mid = start+(end-start)/2;
TreeNode* root = new TreeNode(num[mid]);
root->left = sortedArrayToBSTUtil(num, start, mid-1);
root->right = sortedArrayToBSTUtil(num, mid+1, end);
return root;
}
TreeNode *sortedArrayToBST(vector<int> &num) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
return sortedArrayToBSTUtil(num, 0, num.size()-1);
}
};
本文详细介绍了使用C++将排序数组转换为二叉搜索树的方法,通过递归调用函数实现数组元素到二叉搜索树节点的映射。
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