1017. Queueing at Bank (25)

参考自:

考察排队事件的模拟

#include<iostream>
#include<iomanip>
#include<queue>
using namespace std;

struct window
{
   int mm;
   int hh;
   int ss;
   bool operator<(const window& a)const
   {
       if(hh>a.hh)
           return true;
      else if(hh==a.hh&&mm>a.mm)
          return true;
     else if(hh==a.hh&&mm==a.mm&&ss>a.ss)
         return true;
     else
         return false;
    }
};

struct customer
{
    int h;
    int m;
    int s;
    int last;
 bool operator<(const customer& a)const
 {
     if(h>a.h)
       return true;
     else if(h==a.h&&m>a.m)
       return true;
     else if(h==a.h&&m==a.m&&s>a.s)
       return true;
     else
       return false;
  }
};

priority_queue<window> bank;
priority_queue<customer> cu;

int main()
{ 
    int n,k,i;
    cin>>n>>k;
    window w;
    for(i=0;i<k;i++)
    {
        w.ss=0;
        w.mm=0;
        w.hh=8;
        bank.push(w);
     }
    customer cust;
    for(i=0;i<n;i++)
    {
        cin>>cust.h;
        getchar();
        cin>>cust.m;
        getchar();
        cin>>cust.s>>cust.last;
       cu.push(cust);
    }
    int c=0;
    double total=0;
    while(!cu.empty())
    {
         cust=cu.top();
         cu.pop();
         if(cust.h>17||(cust.h==17&&cust.m)||(cust.h==17&&!cust.m&&cust.s))
             break;
         c++;
        w=bank.top();
        bank.pop();
       if(cust.h<w.hh||(cust.h==w.hh&&cust.m<w.mm)||(cust.h==w.hh&&cust.m==w.mm&&cust.s<w.ss))
       {
            total+=(w.hh-cust.h)*60.0+(w.mm-cust.m)+(w.ss-cust.s)/60.0;
            w.mm+=cust.last;
            w.hh+=w.mm/60;
            w.mm%=60;
      }
      else  //have window but the customer not come yet  so no need to wait
      {
            w.ss=cust.s;
            w.mm=cust.m+cust.last;
			w.hh=cust.h+w.mm/60;
            w.mm%=60;
       }
      bank.push(w);
   }
 cout<<fixed<<setprecision(1)<<total/c<<endl;
 return 0;
}


 

 

### 银行排队问题的Python实现 银行排队问题是典型的并行处理和任务分配场景,可以通过ZeroMQ框架中的Ventilator-Worker-Sink模型来解决[^1]。以下是基于该模型的一个简单Python实现: #### ZeroMQ Ventilator 实现 Ventilator负责生成任务并将它们发送给Workers。 ```python import zmq import time context = zmq.Context() # Socket to send tasks to workers sender = context.socket(zmq.PUSH) sender.bind("tcp://*:5557") print("Press Enter when the workers are ready...") _ = input() print("Sending tasks to workers...") # Send out tasks total_msec = 0 for task_nbr in range(100): workload = int((task_nbr * task_nbr) % 100 + 1) # Some random work load total_msec += workload sender.send_string(str(workload)) print(f"Total expected cost: {total_msec} msec") time.sleep(1) # Give 0MQ time to deliver ``` #### ZeroMQ Worker 实现 Worker接收来自Ventilator的任务并执行计算后将结果返回给Sink。 ```python import zmq import sys import time context = zmq.Context() # Socket to receive messages on receiver = context.socket(zmq.PULL) receiver.connect("tcp://localhost:5557") # Socket to send messages to sender = context.socket(zmq.PUSH) sender.connect("tcp://localhost:5558") while True: s = receiver.recv_string() print(f"Received request: {s}") # Do some 'work' time.sleep(int(s) / 10) # Send results to sink sender.send(b'') ``` #### ZeroMQ Sink 实现 Sink收集所有Worker的结果,并统计完成时间。 ```python import zmq import time context = zmq.Context() # Socket to collect worker responses receiver = context.socket(zmq.PULL) receiver.bind("tcp://*:5558") # Wait for start of batch s = receiver.recv() # Start our clock now tstart = time.time() # Process 100 confirmations for task_nbr in range(100): s = receiver.recv() if task_nbr % 10 == 0: sys.stdout.write(':') else: sys.stdout.write('.') sys.stdout.flush() # Calculate and report duration of batch tend = time.time() print(f"\nTotal elapsed time: {(tend-tstart)*1000} msec") ``` 上述代码展示了如何通过ZeroMQ构建一个简单的分布式任务管理系统[^2]。对于银行排队问题,可以将其视为多个客户作为任务被分配到不同的柜员(即Worker),而最终的结果由Sink汇总。 此外,在高并发环境下,还需要注意内存管理和I/O性能优化[^3]。建议使用缓存机制减少磁盘操作频率,并利用消息队列实现各模块间的异步通信。
评论 1
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包

打赏作者

AI记忆

你的鼓励将是我创作的最大动力

¥1 ¥2 ¥4 ¥6 ¥10 ¥20
扫码支付:¥1
获取中
扫码支付

您的余额不足,请更换扫码支付或充值

打赏作者

实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值