删除相同字符问题－－－关于fgets

最新推荐文章于 2025-08-05 13:48:03 发布

stary_yan

最新推荐文章于 2025-08-05 13:48:03 发布

阅读量484

点赞数

CC 4.0 BY-SA版权

分类专栏： c语言编程

本文链接：https://blog.youkuaiyun.com/stary_yan/article/details/50476363

c语言编程专栏收录该内容

66 篇文章

订阅专栏

本文提供了一种从一个字符串中删除另一个字符串包含的所有字符的方法，并通过两个示例程序进行了解释。程序使用C语言实现，适用于初学者理解字符串操作的基础概念。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

In this exercise, you will get two strings A and B in each test group and the length of every string is less than 40, you need to delete all characters which are contained in string B from string A.

The character may be space or letter.

Input

first line is a number n(0

#include <stdio.h>
#include <string.h>
char input1[50];
char input2[50];
int main() {
    int n;
    scanf("%d", &n);
    getchar();
    while (n--) {
        memset(input1, 0, sizeof(input1));
        memset(input2, 0, sizeof(input2));
        fgets(input1, 50, stdin);
        fgets(input2, 50, stdin);
        long length1 = strlen(input1);
        long length2 = strlen(input2);
        for (int i = 0; i < length1; i++) {
            for (int j = 0; j < length2; j++) {
                if (input1[i] == input2[j]) {
                    input1[i] = '!';
                }
            }
        }
        for (int i = 0; i < length1; i++) {
            if (input1[i] != '!') {
                printf("%c", input1[i]);
            }
        }
        printf("\n");
    }
    return 0;
}

过不了测试，但输出正确。

#include <stdio.h>
#include <string.h>
char input1[50];
char input2[50];
int main() {
    int n;
    scanf("%d", &n);
    while (n--) {
        char temp;
        scanf(" %c", &temp);
        int length1 = 0;
        while (temp != '\n') {
            input1[length1++] = temp;
            scanf("%c", &temp);
        }
        scanf(" %c", &temp);
        int length2 = 0;
        while (temp != '\n') {
            input2[length2++] = temp;
            scanf("%c", &temp);
        }
        for (int i = 0; i < length1; i++) {
            for (int j = 0; j < length2; j++) {
                if (input1[i] == input2[j]) {
                    input1[i] = '!';
                }
            }
        }
        for (int i = 0; i < length1; i++) {
            if (input1[i] != '!') {
                printf("%c", input1[i]);
            }
        }
        printf("\n");
    }
    return 0;
}