1129 Recommendation System

本文介绍了一个简单的推荐系统设计,该系统通过记录用户访问物品的频率来预测用户的偏好,并实时给出推荐列表。输入包括一系列用户访问的物品索引,输出则是针对每个访问的个性化推荐列表,按访问频率降序排列。

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1129 Recommendation System
Recommendation system predicts the preference that a user would give to an item. Now you are asked to program a very simple recommendation system that rates the user’s preference by the number of times that an item has been accessed by this user.

Input Specification:
Each input file contains one test case. For each test case, the first line contains two positive integers: N (≤ 50,000), the total number of queries, and K (≤ 10), the maximum number of recommendations the system must show to the user. Then given in the second line are the indices of items that the user is accessing – for the sake of simplicity, all the items are indexed from 1 to N. All the numbers in a line are separated by a space.

Output Specification:
For each case, process the queries one by one. Output the recommendations for each query in a line in the format:

query: rec[1] rec[2] … rec[K]
where query is the item that the user is accessing, and rec[i] (i=1, … K) is the i-th item that the system recommends to the user. The first K items that have been accessed most frequently are supposed to be recommended in non-increasing order of their frequencies. If there is a tie, the items will be ordered by their indices in increasing order.

Note: there is no output for the first item since it is impossible to give any recommendation at the time. It is guaranteed to have the output for at least one query.

Sample Input:
12 3
3 5 7 5 5 3 2 1 8 3 8 12
Sample Output:
5: 3
7: 3 5
5: 3 5 7
5: 5 3 7
3: 5 3 7
2: 5 3 7
1: 5 3 2
8: 5 3 1
3: 5 3 1
8: 3 5 1
12: 3 5 8

#include<iostream>
#include<set>
#define N 50005
using namespace std;
struct node {
	node(int a, int b): val(a), cnt(b) {};
	int val,cnt;
	bool operator < (const node a)const {
		if (cnt != a.cnt) return cnt > a.cnt;
		else return val < a.val;
   }
};
int name[N];
int main()
{
	int n, k, a;
	set<node>s;
	scanf_s("%d%d", &n, &k);
	for (int i = 1; i <= n; i++) {
		scanf_s("%d", &a);
		if (i != 1) {
			int tempCnt = 0;
			printf("%d:", a);
			for (auto it = s.begin(); it != s.end() && tempCnt < k; tempCnt++, it++) 
				printf(" %d", it->val);
			printf("\n");
		}
		auto it = s.find(node(a, name[a]));
		if (it != s.end()) s.erase(it);
		name[a]++;
		s.insert(node(a, name[a]));
	}

	return 0;
}
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