290. Word Pattern【E】【47】

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#leetcode #python #字符串

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本文介绍了一种用于判断字符串是否遵循给定模式的算法。通过建立字母与非空单词之间的双射映射，该算法能够有效地解决模式匹配问题，并提供了具体的实现代码及示例。

Given a pattern and a string str, find if str follows the same pattern.

Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.

Examples:

pattern = "abba", str = "dog cat cat dog" should return true.
pattern = "abba", str = "dog cat cat fish" should return false.
pattern = "aaaa", str = "dog cat cat dog" should return false.
pattern = "abba", str = "dog dog dog dog" should return false.

Notes:
You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.

Credits:
Special thanks to @minglotus6 for adding this problem and creating all test cases.

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class Solution(object):
    def wordPattern(self, pattern, str):
        #print pattern,str
        p = pattern
        str = str.split(' ')
        #print str
        dic = {}
        #print dic,len(str)

        if len(str) != len(p):
            return False

        for i in xrange(len(str)):
            if p[i] not in dic:
                if str[i] in dic.values():
                    return False
                dic[p[i]] = str[i]
            else:

                if dic[p[i]] != str[i]:
                    return False

        return True