Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
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就是用最简单直白的一位一位做
class Solution(object):
def reverseBits(self, n):
res = [0]*32
i = 0
while n>0:
res[i]= n&1
n = n >> 1
i += 1
i = 31
r = 0
for j in res:
if j:
r += 1<<i#pow(2,i)
i -= 1
return r
"""
:type n: int
:rtype: int
"""

本文介绍了一种方法来反转一个给定的32位无符号整数的所有位,并提供了一个Python实现的例子。例如,输入43261596(二进制为00000010100101000001111010011100),输出964176192(二进制为00111001011110000010100101000000)。讨论了如何优化此过程以提高效率。

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