printf 和scanf的%*s, %*d的作用

#include<stdio.h>
int main()
{
        int i;
        char str[1024];

        printf("Enter text: ");
        scanf("%*s", &str);
        printf("%s\n", str);

        printf("Enter interger: ");
        scanf("%*d", &i);
        printf("%d\n", i);
        return 0;
}

输出

manav@workstation:~$ gcc -Wall -pedantic d.c
d.c: In function ‘main’:
d.c:8: warning: too many arguments for format
d.c:12: warning: too many arguments for format
manav@manav-workstation:~$ ./a.out
Enter text: manav
D
Enter interger: 12345
372
manav@workstation:~$

scanf 中使用*d是跳过的意思

int a=1,b=2,c=3;
    scanf("%d %*d %d",&a,&b,&c); //input is given as: 10 20 30

结果是

a=10 b=30 and c=3;  // 20 is skipped

再比如:

<pre name="code" class="cpp">scanf("#%f:%*d:%*d:%*d\n", &num[0]);//#1.33:3:4:5

结果就是num[0] = 2.33

注:原文来自 http://stackoverflow.com/questions/2155518/what-is-scanfs-and-scanfd-format-identifiers