hdu2057

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

0
2C
11
-2C
-90

/*注意输出的例如-2C大写字母c,如果用%I64x输出的则是小写c*/

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
    __int64 a, b, sum;  //__int64最大能表示16位16进制
    while(scanf("%I64X%I64X", &a, &b) != EOF){
        sum = a + b;
        if(sum < 0)
            printf("-%I64X\n", -sum);    //16进制表示负数的时候是补码所以要注意
        else
            printf("%I64X\n", sum);
    }
    return 0;
}