【1】【并查集】HDU1856 More is better

本文介绍了一个基于并查集算法的经典问题:如何找出最大的互为朋友的群体。通过给定的直接朋友对,利用并查集进行分组,并记录每组的人数,最终找出人数最多的那组。

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More is better

Time Limit: 5000/1000 MS (Java/Others)
Memory Limit: 327680/102400 K (Java/Others)

Problem Description
Mr Wang wants some boys to help him with a project. Because the project is rather complex, the more boys come, the better it will be. Of course there are certain requirements.

Mr Wang selected a room big enough to hold the boys. The boy who are not been chosen has to leave the room immediately. There are 10000000 boys in the room numbered from 1 to 10000000 at the very beginning. After Mr Wang’s selection any two of them who are still in this room should be friends (direct or indirect), or there is only one boy left. Given all the direct friend-pairs, you should decide the best way.

Input
The first line of the input contains an integer n (0 ≤ n ≤ 100 000) - the number of direct friend-pairs. The following n lines each contains a pair of numbers A and B separated by a single space that suggests A and B are direct friends. (A ≠ B, 1 ≤ A, B ≤ 10000000)

Output
The output in one line contains exactly one integer equals to the maximum number of boys Mr Wang may keep.

Sample Input
4
1 2
3 4
5 6
1 6
4
1 2
3 4
5 6
7 8

Sample Output
4
2

Hint

A and B are friends(direct or indirect), B and C are friends(direct or indirect),
then A and C are also friends(indirect).

In the first sample {1,2,5,6} is the result.
In the second sample {1,2},{3,4},{5,6},{7,8} are four kinds of answers.

链接
HDU1856

题意
有n对数(a,b),每一对数表示两个人是直接的朋友,朋友的朋友也是间接的朋友。问最多的一个朋友集合里有多少人?

分析
16/8/13最基础的并查集,要在父节点处记录一下每个组的人数,最后sort一遍输出最大值即可。(基础并查集模板)

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