You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
time: o(max(m,n))
space: o(m+n)
<span style="font-size:14px;">/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
int carry=0;
ListNode head=new ListNode(0);
ListNode result=head;
while(l1!=null||l2!=null){
if(l1!=null){
carry+=l1.val;
l1=l1.next;
}
if(l2!=null){
carry+=l2.val;
l2=l2.next;
}
head.next=new ListNode(carry%10);
head=head.next;
carry/=10;
}
if(carry==1){
head.next=new ListNode(1);
}
return result.next;
}
}</span>