Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011
, so the function should return 3.
向左移位就是在低位补0,向右移位就是在高位补0,按位与1作比较。
class Solution {
public:
int hammingWeight(uint32_t n) {
int ans = 0;
while(n) {
ans += n & 1;
n = n>>1;
}
return ans;
}
};