Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without
repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1.
class Solution {
public:
int lengthOfLongestSubstring(string s)
{
if(s.size() == 0)
return 0;
int start = 0;
int maxlen = 1;
int flag[256];
memset(flag,-1,sizeof(int)*256);
for(int i = 0; i < s.size(); i++)
{
if(flag[s[i]] >= start)
{
maxlen = maxlen > i - start? maxlen : i - start;
start = flag[s[i]] + 1;
}
flag[s[i]] = i;
}
maxlen = maxlen > s.size() - start ? maxlen : s.size()-start;
return maxlen;
}
};int flag[256];
memset(flag,-1,sizeof(int)*256);不能改为int flag[256] = {-1};//只有第一个元素被赋值为-1,其余为0
本文介绍了一种求解字符串中最长无重复字符子串长度的高效算法,并提供了详细的C++实现代码。通过使用滑动窗口技术和哈希表,该算法能够在O(n)的时间复杂度内解决问题。
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