Lambda Expressions(Sort)

Lambda Expressions

Use lambda expression to implement sort directly,no need to use new function.

    @Test(dataProvider = "persons")
    public void testSortPersons4(Person[] persons) {
        List<Person> personCollection = Arrays.asList(persons);
        personCollection.sort(Comparator.comparing((person) -> person.getAge()));
        assertSortedPersons(personCollection.toArray(persons));
    }

    @Test(dataProvider = "persons")
    public void testSortPersons5(Person[] persons) {
        List<Person> personCollection = Arrays.asList(persons);
        personCollection.sort(Comparator.comparing(Person::getAge));
        assertSortedPersons(personCollection.toArray(persons));
    }

    @Test(dataProvider = "persons")
    public void testSortPersons6(Person[] persons) {
        List<Person> personCollection = Arrays.asList(persons);
        personCollection.sort(Comparator.comparing(Person::getAge).thenComparing(Person::getName));
        assertSortedPersons(personCollection.toArray(persons));
    }

• Use multi sort condition

    @Test(dataProvider = "persons")
    public void testSortPersons7(Person[] persons) {
        List<Person> personCollection = Arrays.asList(persons);
        personCollection
                .sort(Comparator.comparing(Person::getAge).reversed().reversed().thenComparing(Person::getName));
        assertSortedPersons(personCollection.toArray(persons));
    }

    @Test(dataProvider = "persons")
    public void testSortPersons8(Person[] persons) {
        List<Person> personCollection = Arrays.asList(persons);
        personCollection.sort((person1, person2) -> {
            int ageCompare = person1.getAge() - person2.getAge();
            return ageCompare != 0 ? ageCompare : person1.getName().compareTo(person2.getName());
        });
        assertSortedPersons(personCollection.toArray(persons));
    }