Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
CC150 原题
class MinStack {
Node top = null;
public void push(int x) {
if(top == null) {
top = new Node(x);
top.min = x;
} else {
Node temp = new Node(x);
temp.next = top;
temp.min = Math.min(x, top.min);
top = temp;
}
}
public void pop() {
top = top.next;
return;
}
public int top() {
if(top != null)
return top.val;
else
return 0;
}
public int getMin() {
if(top != null)
return top.min;
else
return 0;
}
class Node {
int val;
int min;
Node next;
public Node(int val) {
this.val = val;
}
}
}

本文介绍了一个特殊的数据结构——最小值栈,它能在常数时间内完成压栈、弹栈、获取栈顶元素及获取当前栈中最小元素的操作。通过自定义节点类并维护每个节点的最小值信息,确保了所有操作的时间复杂度均为O(1)。
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