404. Sum of Left Leaves
Find the sum of all left leaves in a given binary tree.
Example:
3
/ \
9 20
/ \
15 7
There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
解法
递归找出每个结点的左结点再相加。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public int sumOfLeftLeaves(TreeNode root) {
if (root == null) {
return 0;
}
int ans = 0;
if (root.left != null) {
if (root.left.left == null && root.left.right == null) {
ans += root.left.val;
} else {
ans += sumOfLeftLeaves(root.left);
}
}
ans += sumOfLeftLeaves(root.right);
return ans;
}
}