342. Power of Four
Given an integer (signed 32 bits), write a function to check whether it is a power of 4.
Example:
Given num = 16, return true. Given num = 5, return false.
Follow up: Could you solve it without loops/recursion?
解法一
对数法
public class Solution {
public boolean isPowerOfFour(int n) {
return (Math.log10(n) / Math.log10(4)) % 1 == 0;
}
}
解法二
public class Solution {
public boolean isPowerOfFour(int num) {
return num > 0 && (num & (num - 1)) == 0 && (num - 1) % 3 == 0;
}
}
解法三
4:100;16:10000,奇数位为0
public class Solution {
public boolean isPowerOfFour(int num) {
return num > 0 && (num&(num-1)) == 0 && (num & 0x55555555) != 0;
}
}