C++实现两个线程交替打印奇数和偶数，一直到10

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#c++ #算法 #开发语言

两个线程交替打印奇数和偶数，一直到10。
用mutex来实现。参考的网上的代码。

#include <iostream>
#include <thread>
#include <mutex>

using namespace std;

int number;
mutex mutex_1;

const int MAXNUM = 10;

void printOdd() {
    while (1) {
        mutex_1.lock();
        if (number >= MAXNUM) {
            mutex_1.unlock();
            break;
        }
        if (number % 2 == 0) {
            number++;
            cout << "mythread_1: " << number << endl;
        }

        mutex_1.unlock();
    }
    cout  << "mythread_1 finish" << endl;
}

void printEven() {
    while (1) {
        mutex_1.lock();

        if (number >= MAXNUM) {
            mutex_1.unlock();
            break;
        }
        if (number % 2 == 1) {
            number++;
            cout << "mythread_2: " << number << endl;
        }

        mutex_1.unlock();
    }
    cout  << "mythread_2 finish" << endl;
}

int main() {
    number = 0;

    cout << endl << "Create and Start!" << endl;

    thread mythread_1(printOdd);
    thread mythread_2(printEven);

    mythread_1.join();
    mythread_2.join();

    cout << endl << "Finish and Exit!" << endl;
    return 0;
}