zoj 1530 Find The Multiple

//前几天做了个1136,看到这题和它挺相似的不过此题没用BFS做,偷了懒看别人都是用dfs加随机化算法做的

学习一下。因为题目要求任意结果都是accepttable,可以用随机化算法优化。为了防止一直向左或右搜索。

#include<cstdio>
#include<stdlib.h>
#include<time.h>
#include<cstring>
#define MAX 99
int n;
int num[MAX];
bool flag;

void print(int *a,int len)
{

    int i=0;

    while(i<len)
        printf("%d",a[i++]);

    printf("\n");
    return ;
}
void dfs(int *num, int depth,int r)
{
    if(depth>MAX||flag) return  ;
    int temp=r*10;
    if(!(temp%n))
    {
        num[depth-1]=0;
        print(num,depth);
        flag=true;
    }
    if(!(temp+1)%n)
    {

        num[depth-1]=1;
        print(num,depth);
        flag=true;

    }
    if(rand()&1)
    {

        num[depth-1]=1;
        dfs(num,depth+1,(temp+1)%n);
        num[depth-1]=0;
        dfs(num,depth+1,temp%n);

    }
    else
    {

        num[depth-1]=0;
        dfs(num,depth+1,temp%n);
        num[depth-1]=1;
        dfs(num,depth+1,(temp+1)%n);
    }
    return ;
}

int main()
{
    srand((unsigned)time(NULL)); //设置随机数种子
    while(scanf("%d",&n))
    {

        if(n==0) break;
        flag=false;
        memset(num,0,sizeof(num));
        num[0]=1;
        dfs(num,2,1);
    }

    return 0;
}


第五届广西省大学生程序设计竞赛K Kirby's challenge(AC代码) 分数 300 作者 Colin 单位 杭州电子科技大学 Description Recently, Colin bought a Switch for Eva. And they are playing "Kirby and the Forgotten Land". In a challenge mission, Kirby is in a 4×n grid. The row of it is numbered from 1 to 4, and the column of it is numbered from 1 to n. There are many keys in this grid. Let a x,y ​ represent the status of cell (x,y). If a x,y ​ =1, there is a key in (x,y). If a x,y ​ =0, there is no key in (x,y). Kirby starts at (1,1), and should reach (4,n). Moreover, Kirby must collect all the keys in the grid to open the door in (4,n). Kirby will collect the key at (x,y) when Kirby reach (x,y). Of course, Kirby will collect the key at (1,1) at the beginning. In a second, Kirby can move from (x,y) to (x+1,y),(x,y+1),(x−1,y). Or Kirby can stay at (x,y) and throw a returnable flying weapon(boomerang) to collect keys in the flying path. Kirby has two ways to throw the weapon. As the picture shows: image-20220604213457062.png The flying path is represented as the grey cells, so keys in the grey cells can be collected by the weapon. In a second, Kirby can only choose one way to throw the weapon, but Kirby can throw the weapon multiple times at (x,y) if necessary. Notice: Kirby can't get off the grid, but the weapon can fly outside the grid and keep the flying path. Please write a program to help Colin and Eva find the shortest time to complete the challenge mission, so that they can get more rewards. Input The first line contains one integer n (1≤n≤100). In the next 4 lines, the x-th line contains n integers a x,1 ​ ,a x,2 ​ ,⋯,a x,n ​ (0≤a x,y ​ ≤1). Output Print one integer representing the minimum number of seconds required to complete the challenge mission. Sample input 1 5 1 1 1 0 0 0 1 0 1 0 0 0 1 0 0 0 0 0 0 1 output 1 8 The best solution is: Spend 1 second to throw the weapon in the second way at (1,1), and spend 7 seconds to reach (4,5). 代码长度限制 16 KB 时间限制 1000 ms 内存限制 512 MB 栈限制 131072 KB
08-09
先看效果: https://renmaiwang.cn/s/jkhfz Hue系列产品将具备高度的个性化定制能力,并且借助内置红、蓝、绿三原色LED的灯泡,能够混合生成1600万种不同色彩的灯光。 整个操作流程完全由安装于iPhone上的应用程序进行管理。 这一创新举措为智能照明控制领域带来了新的启示,国内相关领域的从业者也积极投身于相关研究。 鉴于Hue产品采用WiFi无线连接方式,而国内WiFi网络尚未全面覆盖,本研究选择应用更为普及的蓝牙技术,通过手机蓝牙与单片机进行数据交互,进而产生可调节占空比的PWM信号,以此来控制LED驱动电路,实现LED的调光功能以及DIY调色方案。 本文重点阐述了一种基于手机蓝牙通信的LED灯设计方案,该方案受到飞利浦Hue智能灯泡的启发,但考虑到国内WiFi网络的覆盖限制,故而选用更为通用的蓝牙技术。 以下为相关技术细节的详尽介绍:1. **智能照明控制系统**:智能照明控制系统允许用户借助手机应用程序实现远程控制照明设备,提供个性化的调光及色彩调整功能。 飞利浦Hue作为行业领先者,通过红、蓝、绿三原色LED的混合,能够呈现1600万种颜色,实现了全面的定制化体验。 2. **蓝牙通信技术**:蓝牙技术是一种低成本、短距离的无线传输方案,工作于2.4GHz ISM频段,具备即插即用和强抗干扰能力。 蓝牙协议栈由硬件层和软件层构成,提供通用访问Profile、服务发现应用Profile以及串口Profiles等丰富功能,确保不同设备间的良好互操作性。 3. **脉冲宽度调制调光**:脉冲宽度调制(PWM)是一种高效能的调光方式,通过调节脉冲宽度来控制LED的亮度。 当PWM频率超过200Hz时,人眼无法察觉明显的闪烁现象。 占空比指的...
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