# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
if root is None:
return root
root.left =self.invertTree(root.left)
root.right=self.invertTree(root.right)
root.left,root.right = root.right,root.left
return root
226. 翻转二叉树
最新推荐文章于 2025-05-10 18:09:08 发布