Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.
Input The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input 2 6 19 0Sample Output
10 100100100100100100 111111111111111111
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <vector>
using namespace std;
typedef long long ll;
int t, n, m, flag;
void DFS(int cur, ll num) {
if(cur == 19 || flag) {
return;
}
if(num % n == 0) {
cout << num << endl;
flag = 1;
return;
}
DFS(cur + 1, num * 10);
DFS(cur + 1, num * 10 + 1);
}
int main() {
ios::sync_with_stdio(false);
while(cin >> n && n) {
flag = 0 ;
DFS(0, 1);
}
return 0;
}