摘要
本题考察了考生对于python数据结构的理解能力,如果能想到字典型具有键值不可重复的特性就能很轻松完成
原题
This time, you are supposed to find A+B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:
K N1 aN1 N2 aN2 ... NK aNK
where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10,0≤NK<⋯<N2<N1≤1000.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input:
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output:
3 2 1.5 1 2.9 0 3.2
题目意思
现在有两个多项式A,B,分别用两行数据表示,其中每一行有K个数据,每个数据由次数和系数组成,现在要把两个多项式相加,问最终输出的多项式的每个次幂及其系数是多少。
本题的例子中A:2.4x + 3.2 B:1.2x^2 + 0.5x 两个式子相加就是1.2x^2 + 2.9x + 3.2
思路
python中字典具有键值不可重复的特性,那么只要先将a中的键值和数据先保存进result字典中,然后遍历b,把b中的数据放入与a键值相同的地方,最后逆序排序输出即可。
Python代码
# 输入数据,并保留本来的数据格式
a = [eval(i) for i in input().split()[1:]]
b = [eval(i) for i in input().split()[1:]]
result = {}
# 分别把数据存放入字典
for i in range(0, len(a), 2):
result[a[i]] = result.get(a[i], 0) + a[i + 1]
for i in range(0, len(b), 2):
result[b[i]] = result.get(b[i], 0) + b[i + 1]
# 删除系数为0的项
for i in list(result.keys()):
if result[i] == 0:
del result[i]
result = sorted(result.items(), key=lambda d: int(d[0]), reverse=True)
# 输出元素
print(len(result), end="")
for tup in result:
print(" {} {:.1f}".format(tup[0], tup[1]), end="")