XTU OJ 1234 Legal Identifier

最新推荐文章于 2025-08-03 19:27:56 发布

原创最新推荐文章于 2025-08-03 19:27:56 发布 · 495 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#c语言

湘大oj 专栏收录该内容

62 篇文章

订阅专栏

本文介绍了一个使用C语言编写的程序，该程序能够检查输入的标识符是否为C语言的关键字，并验证标识符的有效性。通过对输入字符串进行一系列判断，包括特判首位不能为数字、限定长度范围以及比对预设关键字列表，程序可以准确地识别并反馈结果。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

//首先特判掉第一个为数字的 
//然后从第一个（a1）开始判断，锁定串长遍历，如果出现就Break,如果没有则继续。
//strcmp()函数。
#include<stdio.h>
#include<string.h>
char a[34][10]={"auto","break","case","char","const","continue","default","do","double","else","enum",
"extern","float","for","goto","if","int","long","register","return","short","signed","sizeof","static",
"struct","switch","typedef","union","unsigned","void","volatile","while"} ;
char num[34];
int  main()
{
    int k;
    scanf("%d",&k);
    while(k--){
        int flag=1;
        scanf("%s",num);
        int n=strlen(num);
        for(int i=0;i<n;i++){
                if(num[0]>='0'&&num[0]<='9'){
                    flag=0;
                    break;
                   }
                if(num[i]>='0'&&num[i]<='9'||num[i]>='a'&&num[i]<='z'||num[i]>='A'&&num[i]<='Z'||num[i]=='_'){
                    continue;
                   }
                else{
                    flag=0;
                    break;
                }
        }
            if(flag){
                if(n>=2&&n<=8){
                    for(int i=0;i<32;i++){
                        if(strcmp(num,a[i])==0){
                            flag=0;
                            break;
                        }
                        else continue;
                    }
                }
            }
        if(flag==0)    printf("No\n");
        else         printf("Yes\n");
        }
    return 0;
}