使用BigDecimal解决double在进行小数运算时的精度损失

public class Test {
    public static void main(String[] args) {
        double d = 0.09;
        double d1 = 0.01;
        System.out.println(d + d1);//0.09999999999999999

        BigDecimal bigDecimal = BigDecimal.valueOf(0.09);
        BigDecimal bigDecimal1 = BigDecimal.valueOf(0.01);
        System.out.println(bigDecimal.add(bigDecimal1));//0.10

        BigDecimal bigDecimal3 = BigDecimal.valueOf(8.22);
        BigDecimal bigDecimal4 = BigDecimal.valueOf(2.15);

//        报错:Non-terminating decimal expansion
//        System.out.println(bigDecimal3.divide(bigDecimal4));


        System.out.println(bigDecimal3.divide(bigDecimal4, 2, RoundingMode.HALF_UP));//四舍五入保留两位
    }
}