将二进制数字串转化为一维矩阵

将二进制数字串转化为一维矩阵

import numpy as np
m = 1000010
A = np.empty((1, 7))
for i in range(7):
    j = 6 - i
    a = m % 10           # A[i] = a  i = i - 1
    A[0][j] = a
    m = int(m / 10)
print(A)

运行结果展示如上图在这里插入图片描述