POJ3017 Cut the Sequence(单调队列优化dp)好题!!必做!!

该博客介绍了如何使用单调队列优化动态规划来解决POJ3017问题。问题要求将一个整数序列切割成连续子序列,每个子序列和不超过给定值M,目标是最小化所有子序列最大值之和。博客给出了题意解释、解题思路以及代码实现。

Cut the Sequence POJ - 3017

Given an integer sequence { an } of length N, you are to cut the sequence into several parts every one of which is a consecutive subsequence of the original sequence. Every part must satisfy that the sum of the integers in the part is not greater than a given integer M. You are to find a cutting that minimizes the sum of the maximum integer of each part.
Input
The first line of input contains two integer N (0 < N ≤ 100 000), M. The following line contains N integers describes the integer sequence. Every integer in the sequence is between 0 and 1 000 000 inclusively.

Output
Output one integer which is the minimum sum of the maximum integer of each part. If no such cuttings exist, output −1.
Sample Input
8 17
2 2 2 8 1 8 2 1
Sample Output
12
Hint
Use 64-bit integer type to hold M.

题意

在一个长度为n的序列中,切割每段的代价是这段中最大元素的值,且任意一段的和不能超

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