CF
文章平均质量分 91
VigiIante
这个作者很懒,什么都没留下…
展开
专栏收录文章
- 默认排序
- 最新发布
- 最早发布
- 最多阅读
- 最少阅读
-
Codeforces Round #529 (Div. 3) C. Powers Of Two题解及思路
time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Ivan wants to play a game with you. He picked some string ss of length nn consis...原创 2018-12-28 21:15:55 · 249 阅读 · 0 评论 -
Codeforces Round #544 (Div. 3) B. Preparation for International Women's Day题解
https://codeforces.com/contest/1133/problem/B #include<algorithm> #include <iostream> #include <sstream> #include <cstring> #include <cstdlib> #include <string&...原创 2019-03-12 18:42:27 · 1148 阅读 · 0 评论 -
Codeforces Round #544 (Div. 3) D. Zero Quantity Maximization题解
https://codeforces.com/contest/1133/problem/D #include<algorithm> #include <iostream> #include <sstream> #include <cstring> #include <cstdlib> #include <string&...原创 2019-03-12 20:19:16 · 158 阅读 · 0 评论 -
April Fools Day Contest 2019 A. Thanos Sort题解
愚人节专场比我想象的难一些(太菜了) 代码来自一个博客:https://blog.youkuaiyun.com/qq_38185591/article/details/88966801 题目链接:https://codeforces.com/contest/1145/problem/A 主要考验dfs能力,我第一次写了110行代码没过卡题 贴代码: #include<algorithm&...原创 2019-04-02 23:45:33 · 308 阅读 · 0 评论 -
Codeforces Round #554 (Div. 2) Problem B. Neko Performs Cat Furrier Transform
https://codeforces.com/contest/1152/problem/B 大致思路是找到二进制n的第一个0, 然后模拟,与位操作有关 #include<algorithm> #include <iostream> #include <sstream> #include <cstring> #include <cst...原创 2019-04-26 09:46:52 · 165 阅读 · 0 评论 -
Codeforces Round #402 (Div. 2)题解
A. Pupils Redistribution https://codeforces.com/contest/779/problem/A 题意就是把数字1到5平均分到两个班内,题水但是判定容易出BUG #include<bits/stdc++.h> using namespace std; constexpr int maxl = 6; int numa[maxl], num...原创 2019-06-04 10:52:09 · 331 阅读 · 0 评论 -
Codeforces Round #567 (Div. 2) B. Split a Number题解
B. Split a Number time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Dima worked all day and wrote down on a long paper strip his fa...原创 2019-07-02 16:25:05 · 365 阅读 · 0 评论
分享