针对angr提供的练习题,现在进行求解09_angr_hooks,它也是关于hook的问题,需要使用angr求解出正确密码。但是需要提供排除地址以减少路径求解时间。
具体代码如下所示
import angr
import claripy
import sys
def main(argv):
path_to_binary = argv[1]
project = angr.Project(path_to_binary)
initial_state = project.factory.entry_state()
# 此处地址为check_equals_XYMKBKUHNIQYNQXE函数的入口地址
check_equals_called_address = 0x80485a5
#check_equals_XYMKBKUHNIQYNQXE函数所占的长度
instruction_to_skip_length = 0x4d
@project.hook(check_equals_called_address, length=instruction_to_skip_length)
def skip_check_equals_(state):
user_input_buffer_address = 0x804a054 # 输入的buffer
user_input_buffer_length = 0x10 #
user_input_string = state.memory.load(
user_input_buffer_address,
user_input_buffer_length
)
check_against_string = 'XYMKBKUHNIQYNQXE' # 目标字符串
#使用eax存储返回值,如果user_input_string与check_against_string相等则返回1,否则为0
state.regs.eax = claripy.If(
user_input_string == check_against_string,
claripy.BVV(1, 32),
claripy.BVV(0, 32)
)
simulation = project.factory.simgr(initial_state)
def is_successful(state):
stdout_output = state.posix.dumps(sys.stdout.fileno())
return b'Good Job' in stdout_output
def should_abort(state):
stdout_output = state.posix.dumps(sys.stdout.fileno())
return b'Try again' in stdout_output
simulation.explore(find=is_successful, avoid=should_abort)
if simulation.found:
solution_state = simulation.found[0]
# Since we are allowing Angr to handle the input, retrieve it by printing
# the contents of stdin. Use one of the early levels as a reference.
solution = solution_state.posix.dumps(sys.stdin.fileno())
print(solution)
else:
raise Exception('Could not find the solution')
if __name__ == '__main__':
main(sys.argv)
check_equals_XYMKBKUHNIQYNQXE函数的入口地址为0x80485a5,其占用长度为0x80485F2-0x80485a5=0x4d,将它们作为参数输入hook,以跳过check_equals_XYMKBKUHNIQYNQXE函数。
跳过的函数需要输入两个内容,即0x804a054和0x10。
下面验证实验结果
执行刚刚写好的程序,保存为scaffold09.py,并将其与09_angr_hooks放于同一文件夹中,具体如下图所示。
再执行09_angr_hooks,然后需要我们输入angr刚刚求解出的密码,结果为Good Job。
至此,求解09_angr_hooks已全部完成。