自测-5 Shuffling Machine

本文介绍了一种使用自动洗牌机模拟卡牌洗牌过程的方法,通过特定的随机顺序重复洗牌,确保了卡牌的随机性和公平性。文章详细解释了洗牌机的工作原理,包括如何初始化卡牌顺序,如何根据给定的随机顺序进行洗牌,以及如何多次重复这一过程。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

题目

Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid “inside jobs” where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.

The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:

S1, S2, …, S13,
H1, H2, …, H13,
C1, C2, …, C13,
D1, D2, …, D13,
J1, J2

where “S” stands for “Spade”, “H” for “Heart”, “C” for “Club”, “D” for “Diamond”, and “J” for “Joker”. A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.
Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer K (≤20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.
Output Specification:

For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.

Sample Input:
2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47 

Sample Output: 
S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5

代码(c++)

#include <iostream>
#include <string>
using namespace std;

int main()
{
    int time, i, j, k, l, m;
    int move[54];
    cin >> time;//洗牌次数
    string card[] = {"S1","S2","S3","S4","S5","S6","S7","S8","S9","S10","S11","S12","S13",
                     "H1","H2","H3","H4","H5","H6","H7","H8","H9","H10","H11","H12","H13",
                     "C1","C2","C3","C4","C5","C6","C7","C8","C9","C10","C11","C12","C13",
                     "D1","D2","D3","D4","D5","D6","D7","D8","D9","D10","D11","D12","D13",
                     "J1","J2"};//存卡片数组

    string cardbuffer[54];//缓存数组
    for(i=0;i<54;i++)
        cin>>move[i];//移动位置
    for(j=0;j<time;j++)
    {
        for(k=0;k<54;k++)
            cardbuffer[move[k]-1]=card[k];//将一次洗牌后卡片放入缓存数组
        for(l=0;l<54;l++)
            card[l]=cardbuffer[l];//重置card数组
    }
    for(m=0;m<53;m++)
        cout<<cardbuffer[m]<<' ';
    cout<<cardbuffer[53]<<endl;//输出
    return 0;
}
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值