一个投机取巧的方法
vector从后进去
然后在后面到前面输出
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
vector<int> printListReversingly(ListNode* head) {
vector<int>q,q2;
ListNode *now=NULL;
while(head){
q.push_back(head->val);
head=head->next;
}
for(int i=q.size()-1;i>=0;i--){
q2.push_back(q[i]);
}
return q2;
}
};