PAT A1058：A+B in Hogwarts

1058 A+B in Hogwarts (20分)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10^7], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

代码实现(AC)

#include<cstdio>
#include<cstring>
#include<iostream>
#include<string>
using namespace std;
struct Number{
	long long Galleon;
	long long Sickle;
	long long Knut;
};
Number a,b,sum;
void solve()
{
	scanf("%lld.%lld.%lld %lld.%lld.%lld",&a.Galleon,&a.Sickle,&a.Knut,&b.Galleon,&b.Sickle,&b.Knut);
	sum.Knut=(a.Knut+b.Knut)%29;
	sum.Sickle=(a.Sickle+b.Sickle+(a.Knut+b.Knut)/29)%17;
	sum.Galleon=a.Galleon+b.Galleon+(a.Sickle+b.Sickle+(a.Knut+b.Knut)/29)/17;
	printf("%lld.%lld.%lld",sum.Galleon,sum.Sickle,sum.Knut);
}
int main()
{
	solve();
	return 0;	
}