PAT (Advanced Level) Practice 1031 Hello World for U

1031HelloWorldforU编程题解析
本文解析了一道编程题“1031HelloWorldforU”,题目要求将任意长度大于等于5的字符串,按照特定的U形布局打印出来。文章提供了C语言的实现代码,通过计算每边的字符数量,实现了字符串的正确布局。

                                      1031 Hello World for U

Given any string of N (≥5) characters, you are asked to form the characters into the shape of U. For example, helloworld can be printed as:

h  d
e  l
l  r
lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n​1​​ characters, then left to right along the bottom line with n​2​​ characters, and finally bottom-up along the vertical line with n​3​​ characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n​1​​=n​3​​=max { k | k≤n​2​​ for all 3≤n​2​​≤N } with n​1​​+n​2​​+n​3​​−2=N.

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

Sample Output:

h   !
e   d
l   l
lowor

running code:

#include<stdio.h>
#include<string.h>
int main()
{
  char str[100];
  gets(str);
  int N=strlen(str);
  int n1=(N+2)/3,n3=n1,n2=N+2-n1-n3;
  for(int i=0;i<n1-1;i++)
  {
    printf("%c",str[i]);
    for(int j=0;j<n2-2;j++)
    {
      printf(" ");
    }
    printf("%c\n",str[N-i-1]);
  }
  for(int i=0;i<n2;i++)
  {
    printf("%c",str[n1-1+i]);
  }
  return 0;
}

result:

Notice:

当用c++(g++)编译时会出现gets()未声明的编译错误,原因是oj为了公平起见将部分库函数删掉了。

 

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