ctf之AWD(2)_多线程

最新推荐文章于 2024-07-06 10:32:26 发布

「已注销」

最新推荐文章于 2024-07-06 10:32:26 发布

阅读量411

点赞数

分类专栏： ctf Python 文章标签： ctf AWD 多线程

本文链接：https://blog.youkuaiyun.com/qq_38232378/article/details/100903019

版权

ctf 同时被 2 个专栏收录

10 篇文章

订阅专栏

Python

7 篇文章

订阅专栏

ctf之AWD(2)_多线程

# -*- coding:utf-8 -*-
import threading,queue,time

base_url = "http://192.168.1."
url_queue = queue.Queue()

for i in range(1,31):
    url = base_url+str(i)
    url_queue.put(url)

def fetUrl(url_queue):
    while url_queue.qsize()>0:
        try:
            # 不阻塞的读取队列数据
            url = url_queue.get_nowait()
            i = url_queue.qsize()
        except Exception as e:
            print(e)
            break
        print('Current Thread Name %s, Url: %s ' % (threading.currentThread().name, url))

if __name__ == '__main__':
    startTime = time.time()
    threads = []
    threadNum = 4
    for i in range(0,threadNum):
        try:
            t = threading.Thread(target=fetUrl,args=(url_queue,))
            threads.append(t)
        except:
            print("加入线程失败")
            break
    for t in threads:
        try:
            t.start()
        except:
            print('开启线程失败')
            break
    for t in threads:
        try:
            t.join()
        except:
            print('启动线程失败')
            break
    endTime = time.time()
    print('Done, Time cost: %s ' % (endTime - startTime))