WebAPI服务器收发json数据

最新推荐文章于 2025-01-07 16:16:27 发布

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最新推荐文章于 2025-01-07 16:16:27 发布

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分类专栏： Java后端文章标签： java spring

本文链接：https://blog.youkuaiyun.com/qq_37546096/article/details/107084881

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1. 服务端接收

1.1 通过HttpServletRequest request获取json信息

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    @RequestMapping("/dice/init")
    @ResponseBody
    public String diceInit(HttpServletRequest request, Integer Count) {
		String param= null;
		try {
		    BufferedReader streamReader = new BufferedReader( new InputStreamReader(request.getInputStream(),
		            "UTF-8"));//通过I0流获取data body
		    StringBuilder responseStrBuilder = new StringBuilder();
		    String inputStr;
		    while ((inputStr = streamReader.readLine()) != null){
		        responseStrBuilder.append(inputStr);
		    }
		    JSONObject jsonObject = JSONObject.parseObject(responseStrBuilder.toString());
		    param= jsonObject.toJSONString();
		    System.out.println(param);
		} catch (Exception e) {
		    e.printStackTrace();
		}
	}

1.2 使用@RequestBody方法获取

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@RequestMapping("/dice/valueInit")
@ResponseBody
public BaseResponse valueInit(Integer Round, Integer Count, @RequestBody JSONObject obj){
   String userName = obj.getString("userName");
   String steamerName = obj.getString("steamerName");
   String diceUUID = safeUtils.shortMD5(userName+"&"+steamerName+ textUtils.getCurrentTime());
}