HDU1228A + B

Problem Description
读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input
测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output
对每个测试用例输出1行,即A+B的值.

Sample Input
one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

Sample Output
3
90
96

本题代码是我看了别的写的，感觉处理的很干净，贴一下，供自己学习一下。

#include<stdio.h>
#include<string.h>
int main()
{
	char s[100];
	char temp[10];
	char num[10][10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
	while(1)
	{
		int a=0,b=0;
		char s[10];
		while(scanf("%s",s)&&strcmp(s,"+"))
			for(int i=0;i<10;i++)
				if(!strcmp(s,num[i]))
					a=a*10+i;
		while(scanf("%s",s)&&strcmp(s,"="))
			for(int i=0;i<10;i++)
				if(!strcmp(s,num[i]))
					b=b*10+i;
		if(!(a==0&&b==0))
			printf("%d\n",a+b);
		else break;
	}
}