PAT 1054 The Dominant Color python解法

最新推荐文章于 2024-06-28 17:29:14 发布

D_ry

最新推荐文章于 2024-06-28 17:29:14 发布

阅读量408

点赞数

CC 4.0 BY-SA版权

分类专栏： python 用Python刷PAT (Advanced Level) Practice

本文链接：https://blog.youkuaiyun.com/qq_36936510/article/details/85953480

python 同时被 2 个专栏收录

69 篇文章

订阅专栏

用Python刷PAT (Advanced Level) Practice

48 篇文章

订阅专栏

该博客介绍了如何解决PAT 1054问题，即在给定分辨率的图像中找到绝对主导颜色。博主首先解释了原始解法，通过建立数字及其出现次数的字典来寻找最常见的颜色，但这种方法在某些测试用例中导致超时。随后，博主提出了一个优化的解决方案，使用计数变量`count`来跟踪当前主导颜色的出现，当遇到不同颜色时减少计数，直到计数归零时更新主导颜色。这种方法能够有效提高效率，找出图像中占比超过一半的主导颜色。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

1054 The Dominant Color （20 分）
Behind the scenes in the computer’s memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800×600), you are supposed to point out the strictly dominant color.

Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤800) and N (≤600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0,2^24 ). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.

Output Specification:
For each test case, simply print the dominant color in a line.

Sample Input:
5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24
Sample Output:
24

解题思路：建立一个字典，键是数字，值是数字出现的次数。对每个数作如下判断，如果该数在字典里，则将该数对应的值加1，否则，添加一个键值对到字典中，键是该数字，值为1。全部数字判断完成后，只需输出字典中值最大对应的键，即所求。然而，这段代码有一个问题，在2号测试点运行超时。

d={}
col,row = map(int, input().split())
for i in range(row):
    l = list(input().split())
    for j in l:
        if j in d:
            d[j] = d[j]+1
        else:
            d[j] = 1
dominant = max(d,key=d.get)
print(dominant)

新解法： the dominant color肯定是大于总数的一半，可以用一个count计数，开始扫描输入数据，如果dominant和数据中元素相同，将count+1，如果不同将count-1，如果count==0，则更换dominant为当前元素，扫描完成后，dominant即为所求。

col,row = map(int, input().split())
l = []
dominant = 0
count = 0
for i in range(row):
    l = list(input().split())
    for i in l:
        if count == 0:       
            dominant = i
            count += 1
        if dominant == i:
            count += 1
        else:
            count -= 1
print(dominant)