这题主要在于分辨是不是符合要求的数,这个用异常处理可以简单达到
题目简单就直接上代码了:
n = int(input())
x = list(input().split())
num = 0
m = 0
for i in x:
try:
j = float(i)
if -1000 <= j <= 1000 and round(j,2) == j:#在范围内且最多只有两位小数
num +=j
m +=1
else:
print('ERROR: '+str(i)+' is not a legal number')
except:
print('ERROR: ' + str(i) + ' is not a legal number')
if m == 0:
print('The average of 0 numbers is Undefined')
else:
num = num / m
if m == 1:
print('The average of ' + str(m) + ' number is ', end='')
print('%.2f' % (num))
else:
print('The average of ' + str(m) + ' numbers is ', end='')
print('%.2f' % (num))
提交截图:

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