/*
_...---.._
,' ~~"--..
/ ~"-._
/ ~-.
/ . `-.
\ -.\ `-.
\ ~-. `-.
,-~~\ ~.
/ \ `.
. \ `.
| \ .
| \ \
. `. \
\ \
` `. \
` \. \
` \`. \
. \ -. \
` -. \
. ` - \ .
` \ ~- \
` . ~. \
. \ -_ \
` - \
. | ~. \
` | \ \
. | \ \
` | `. \
` ` \ \
. . `. `.
` : \ `.
\ ` \ `.
\ . `. `~~-.
\ : ` \ \
. . \ : `.\
` : \ | | .
\ . \ | |
\ : \ ` | `
. . | |_ .
` `. ` ` | ~.;
\ `. . . .
. `. ` ` `
`. `._. \ `.\
` < \ `. | .
` ` : ` | |
` \ ` | |
`. | \ : .' |
"Are you crying? " ` | \ `_-' |
"It's only the rain." : | | | : ;
"The rain already stopped."` ; |~-.| : '
"Devils never cry." : \ | ` ,
` \` : '
: \` `_/
` .\ "For we have none. Our enemy shall fall."
` ` \ "As we apprise. To claim our fate."
\ | : "Now and forever. "
\ .' : "We'll be together."
: : "In love and in hate"
| .'
| : "They will see. We'll fight until eternity. "
| ' "Come with me.We'll stand and fight together."
| / "Through our strength We'll make a better day. "
`_.' "Tomorrow we shall never surrender."
sao xin*/
#include <vector>
#include <iostream>
#include <string>
//#include <map>
#include <stack>
#include <cstring>
#include <queue>
#include <list>
#include <cstdio>
#include <set>
#include <algorithm>
#include <cstdlib>
#include <cmath>
#include <iomanip>
#include <cctype>
#include <sstream>
#include<functional>
#define INF 0xfffffff
#define eps 1e-6
#define LL long long
using namespace std;
const int N=1e3+5;
const int maxx=1e4+5;
const double q = (1 + sqrt(5.0)) / 2.0; // 黄金分割数
/*
std::hex <<16进制 cin>>std::hex>>a>>std::hex>>b
cout.setf(ios::uppercase);cout<<std::hex<<c<<endl;
b=b>>1; 除以2 二进制运算
//f[i]=(i-1)*(f[i-1]+f[i-2]); 错排
/ for (int i=1; i<=N; i++)
for (int j=M; j>=1; j--)
{
if (weight[i]<=j)
{
f[j]=max(f[j],f[j-weight[i]]+value[i]);
}
}
priority_queue<int,vector<int>,greater<int> >que3;//注意“>>”会被认为错误,
priority_queue<int,vector<int>,less<int> >que4;////最大值优先
//str
//tmp
//vis
//val
//cnt 2486 hdu 3790最短路径
*/
int n,Nn;
double map[N][N];
double dis[N];
int vis[N];
double x[N],y[N];
double dist(double x,double y,double x1,double y1)
{
return sqrt((x-x1)*(x-x1)+(y-y1)*(y-y1));
}
double max(double a,double b)
{
return a>b?a:b;
}
void Dijkstra(int start)
{
double minimum,min;
int k,j,i;
memset(vis,0,sizeof(vis));
for(i=1;i<=n;i++)
dis[i]=map[start][i];
vis[start]=true;
minimum=0;
for(i=1;i<n;i++)
{
min=N;
for(j=1;j<=n;j++)
if(dis[j]<min&&!vis[j])
{
min=dis[j];
k=j;
}
if(i==1)
minimum=min;
vis[k]=true;
if(k==2)
{
cout<<"Scenario #"<<Nn<<endl;
cout<<"Frog Distance = ";
printf("%.3f\n\n",dis[2]);
break;
}
for(j=1;j<=n;j++)
if(dis[j]>max(dis[k],map[k][j])&&!vis[j])
{
dis[j]=max(dis[k],map[k][j]);
}
}
}
int main()
{
int i,j;
Nn=0;
while(cin>>n,n)
{
for(i=1;i<=n;i++)
cin>>x[i]>>y[i];
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
map[i][j]=N;
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
{
map[i][j]=dist(x[i],y[i],x[j],y[j]);
map[j][i]=map[i][j];
}
Nn++;
Dijkstra(1);
}
return 0;
}
poj 2253
最新推荐文章于 2019-10-18 23:26:11 发布