class Solution {
public:
int fib(int n) {
if(n<=1) return n;
vector<int>dp(n+1,0);
dp[1] = 1;
for(int i = 2;i<=n;i++)
{
dp[i] = (dp[i-1]+dp[i-2])%1000000007;
}
return dp[n];
}
};
剑指 Offer 10- I. 斐波那契数列
最新推荐文章于 2023-01-18 18:23:32 发布