int dijkstra(int s, int e) {
priority_queue<P, vector<P>, greater<P>> q;
memset(d, 0x3f, sizeof(d));
d[s] = 0;
q.push(P(0, s));
while (!q.empty()) {
P p = q.top();
q.pop();
if (p.second == e) return d[e];
if (d[p.second]< p.first) continue;
int v = p.second;
for (int i = 1; i<= n; i++) {
if (d[i]>d[v] + G[v][i]) {
d[i] = d[v] + G[v][i];
q.push(P(d[i], i));
}
}
}
return d[e];
}
最短路
最新推荐文章于 2024-10-25 19:32:27 发布