242.有效的字母异位词
哈希表数组法
class Solution:
def isAnagram(self, s: str, t: str) -> bool:
record = [0]*26
for i in s:
record[ord(i)-ord('a')] +=1
for i in t:
record[ord(i)-ord('a')] -=1
for i in range(26):
if record[i] != 0:
return False
return True
对数值进行编制标签哈希表便于寻找是关键
349. 两个数组的交集
字典法
class Solution:
def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]:
table = {}
res = set()
for i in nums1:
table[i] = table.get(i,0) + 1
for i in nums2:
if i in table:
res.add(i)
return list(res)
因为是交集的元素所以不能重复用集合
202. 快乐数
class Solution:
def isHappy(self, n: int) -> bool:
record = set()
while True:
sum = 0
for i in str(n):
sum+=int(i)**2
n = sum
if sum == 1:
return True
if sum in record:
return False
record.add(sum)
退出的循环关键也是循环,一直是循环值,只要再次有循环值就退出,系铃还需系铃人。
1. 两数之和(梦开始的地方)
迷迷糊糊的开始刷题啦
暴力解法:
class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
for i in range(len(nums)):
for j in range(i+1,len(nums)):
if nums[i] + nums[j] == target:
return [i,j]
return []
坚持!
坚持!
坚持就是胜利!!!