题目地址:点击打开链接
思路:挺好的一题
AC代码:
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int dir[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
int diagonal[4][2] = {{-1,-1},{-1,1},{1,-1},{1,1}},visit[25][25];
int m,n,count1;
char map1[25][25];
void dfs(int x,int y)
{
int i,newx,newy;
visit[x][y] = 1;
for(i=0; i<4; i++)//上下左右搜
{
newx = x + dir[i][0];
newy = y + dir[i][1];
if(map1[newx][newy] == 'X' && visit[newx][newy] == 0)
dfs(newx,newy);
else if(map1[newx][newy] == '.')
count1++;
}
for(i=0; i<4; i++)//对角线搜
{
newx = x + diagonal[i][0];
newy = y + diagonal[i][1];
if(map1[newx][newy] == 'X' && visit[newx][newy] == 0)
dfs(newx,newy);
}
}
int main()
{
int i,j;
int click_x,click_y;
while(scanf("%d%d%d%d",&m,&n,&click_x,&click_y))
{
count1 = 0;
if(m + n + click_x + click_y == 0)
break;
memset(map1,'.',sizeof(map1));//在外面围一圈.便于判断
memset(visit,0,sizeof(visit));
for(i=1; i<=m; i++)
{
for(j=1; j<=n; j++)
{
cin>>map1[i][j];
}
}
dfs(click_x,click_y);
printf("%d\n",count1);
}
return 0;
}