应该是一道凯撒加密的题目
```python
str = 'gmbh{ifmmp_dug}'
for my in range(1,26):
for i in str:
mw = ord(i)
if (64 < mw < 91):
jm = mw + my
if jm > 90:
jm = (mw - 26) + my
print(chr(jm), end='')
else:
print(chr(jm), end='')
elif (96 < mw < 123):
jm = mw + my
if jm > 122:
jm = (mw - 26) + my
print(chr(jm), end='')
else:
print(chr(jm), end='')
else:
jm = mw + 0
print(chr(jm), end='')
print(" ")
这是我写的一个脚本