思路:水题,n/a*m/a即可,注意向上取整
#include<bits\stdc++.h>
using namespace std;
#define LL long long
int main()
{
LL n,m,a;
cin >> n >> m >> a;
LL ans =ceil(n/(double)a)*ceil(m/(double)a);
cout << ans << endl;
}
思路:水题,n/a*m/a即可,注意向上取整
#include<bits\stdc++.h>
using namespace std;
#define LL long long
int main()
{
LL n,m,a;
cin >> n >> m >> a;
LL ans =ceil(n/(double)a)*ceil(m/(double)a);
cout << ans << endl;
}